Parallelogram ABCD is reflected over the x-axis. What rule shows the input and output of the reflection, and what is the new coordinate of A'? https://cdn.flvsgl.com/assessment_images/geometry_v15_gs_ca-xml/76546_54075fac/0200_g4_q2.jpg A. (x,y)→(y,-x); A' is at (1, 5) B. (x,y)→(-y,x); A' is at (-1, -5) C. (x,y)→(-x,y); A' is at (5, 1) D. (x,y)→(x,-y); A' is at (-5, -1)
D
Remember that people can't open the links and see it.
lol ok hang on
You need to screenshot it, the links say forbidden when we click on them. I don't know how @KGabriel99 got that answer without seeing it.
you sure @KGabriel99 can you see it?
I can guarantee it. This is VS and I have the notes for it. All x axis reflections are (x,y)->(x,-y)
@iloveyou;* are you taking these questions off an online class test?
Is that segment one?
I have the notes too.
no its hw
• Another way to say "reflect across the x-axis" is to say "reflect across the line y=0" since the line created by graphing y=0 is the same as the x-axis. • An image that is a reflection across the x-axis, or across the line y=0, will have the same x-coordinates as the pre-image but opposite y-coordinates. • Therefore, the rule for reflecting an image across the x-axis can be described as (x, y) → (x, −y).
Yeah he's right .-. I read the question wrong.
Yup.
I appologize @KGabriel99
so D is correct right?
It's fine. Understandable mistake. @MyNameIsNemo
Yes D is correct
thnx guys :D
anytime
Np anytime
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