Question

Subtract, and then simplify, if possible.
b − 3/b + 9
−
b + 2/b − 9

Answer 1

multiply the first whole fraction by b-9 and the whole second fraction by b+9, I'll show you what you should get :)

Answer 2

okay

Answer 3

\[\frac{(b-3)(b-9)}{(b+9)(b-9)}-\frac{(b+9)(b+2)}{(b+9)(b-9)}\] Okay? We needed to get a common denominator, which is \[(b+9)(b-9)\]

Answer 4

We need to expand the numerators in order to subtract them.

Answer 5

for the first one I got b^2

Answer 6

I got b^2 -12b +27 as the numerator

Answer 7

the first one is \[b^2-12b+27\] you are correct

Answer 8

And for the second?

Answer 9

and the second one I got b^2 +11b+18

Answer 10

right. Now, we have one fraction.\[\frac{(b^2-12b+27)-(b^2+11b+18)}{(b+9)(b-9)}\]

Answer 11

So, we then have \[\frac{-23b+9}{(b+9)(b-9)}\]

Answer 12

that's what I got

Answer 13

Awesome. I don't think we can simplify, but let me check.

Answer 14

Thankyou

Answer 15

You're welcome! That's as far as we can simplify haha