A baseball of mass 100 grams is traveling 30m/s when it is caught. In catching the ball player moves his mitt backwards 21 cm and stops. What average force does the ball exert when it is caught?

Question

michele_laino · Answer

here, the work done by the force applied by the player, has to be equal to the kinetic energy of the ball. So we can write:
$$\frac{1}{2}m{v^2} = Fd$$
where $d=21$cm

michele_laino · Answer

from the formula above, i get:
$$F = \frac{{m{v^2}}}{{2d}} = \frac{{0.1 \cdot {{30}^2}}}{{2 \cdot 0.21}} = ...?$$

anonymous · Answer

F=214.285Newton's