Question

A metal wire 1.0 mm in diameter and 2.0 m long has a 6.0-kilogram mass hanging from it. If the wire stretches 1.4mm under the tension, What is the value of young's modulus for metal?

Answer 1

here we can apply this formula:
\[E = \frac{{F/S}}{{\Delta l/l}}\]
where \(E\) is the Young modulus, \(S\) is the cross sectional area of the wire, \(\Delta l\) is the streching of the wire, \(F\) is the applied force. In this case the applied force is equal to the weight, namely:
\(F=m \cdot g\), where, as usually, \(g=9.81\) m/sec^2

Answer 2

I've this(attach)
Am I right?

Answer 3

please wait, I'm working on your solution...

Answer 4

your answer is correct!

Answer 5

Thanks for helping me!

Answer 6

:)