Question

WILL MEDAL AND FAN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A handy man knows from experience that his 29-foot ladder rests in its
most stable position when the distance of its base from a wall is 1 foot farther than the height it reaches up the wall.
A) How far up a wall does this ladder reach? Show your work
B) How far should the base be from the wall?
C) If the man needs to reach a window 25 feet high on the wall, how far from the wall should he place the base of the ladder?

Answer 1

@Austin1617 @mynameisnemo @surjithayer @srizek

Answer 2

x^2 + (x + 1)^2 = 29^2
x^2 + x^2 + 2x + 1 = 841
2x^2 + 2x - 840 = 0
x^2 + x - 420 = 0
x = (-1 +/- sqrt(1 + 1680)) / 2
x = (-1 +/- sqrt(1681)) / 2
x = (-1 +/- 41) / 2
x = -42/2 , 40/2
x = -21 , 20

It's a 20-21-29 foot triangle

a) 20 feet
b) 21 feet

29^2 - 25^2 = x^2
841 - 625 = x^2
216 = x^2
6 * sqrt(6) = x
x = 14.696938456699068589183704448235

14.697 feet

Answer 3

@carlyleukhardt which question does that answer?

Answer 4

@carlyleukhardt ??

Answer 5

@surjithayer

Answer 6

@Michele_Laino can you help with this one maybe?