A 5.0-kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s2, find the force exerted by the rope on the bucket.

Question

anonymous · Answer

newtons second law tells you 

sum of forces = ma 

the forces acting on the bucket are the force of the rope up and gravity down, these combine to create an upward accel of 3 m/s/s 

so we have: 

sum of forces = F-mg = ma 

F-5g=5x3m/s/s 

F=5x9.8+5x3 = 49+15=64N

anonymous · Answer

@undeadknight26 
leggo lol