Question

Medal
Find three consecutive odd integers whose sum is 75.
Write your answers in ascending order.

Answer 1

let n be an an odd integer
the very next odd integer would be n+2 since n+1 is even
and the next one after that would be n+4 since n+3 is even

Answer 2

so let n,n+2, and n+4 be your three odd conseutive integers

Answer 3

add them up and set it's sum to 75

Answer 4

what are the odd integers

Answer 5

n,n+2, and n+4

Answer 6

isnt 2 an even number?

Answer 7

2 is an even number yes
but what does that have to do with our numbers n,n+2,and n+4
where n is odd

Answer 8

okay thank you

Answer 9

n+(n+2)+(n+4)=75
solve for n

Answer 10

then find
n+2
then find
n+4

Answer 11

i dont understand how we solve

Answer 12

do you know how to combine like terms yet?

Answer 13

n+n+n=?
2+4=?

Answer 14

yes

Answer 15

6

Answer 16

and n+n+n=?

Answer 17

3n

Answer 18

n+(n+2)+(n+4)=75
(n+n+n)+(2+4)=75
3n + 6 =75



3n+6=75
can you finish solving?
are you haven't solve linear equations yet?

Answer 19

3n = 69

Answer 20

23

Answer 21

so n=23
so n+2 is?

Answer 22

25

Answer 23

and n+4 is?

Answer 24

27

Answer 25

23,25,27

Answer 26

and can't you agree that 23,25,27 are odd consecutive integers whose sum is 75?

Answer 27

yes i agree

Answer 28

thank you soo much

Answer 29

np