Question

HELP!!!!!!! Algebra 1

Answer 1

\[(\sqrt{2}) (\sqrt[3]{2})\]

Answer 2

How I would I solve this equation

Answer 3

Do you mean:
\[(\sqrt{2})(3\sqrt{2})\]

Answer 4

don't they mean the same thing

Answer 5

I guess so

Answer 6

no, they do not mean the same thing.

Answer 7

what is different between them?

Answer 8

\[\large \sqrt{2} \cdot \sqrt[3]{2} = 2^{1/2} \cdot 2^{1/3} = 2^{(1/2) + (1/3)}\]

Answer 9

Well, think about your exponent rule. \(\large \sqrt[n]{x^m} \implies x^{m/n}\)

Answer 10

I mean this one because, I started doing this but I don't know what to do next

Answer 11

Then when you have something like \(\sqrt{2} \cdot 3\sqrt{2}\) , you can easily factor out the common term, \(\sqrt{2}\) and add the multipliers. \[\sqrt{2} \cdot 3\sqrt{2} = \sqrt{2}(1+3) = 4\sqrt{2}\]

Answer 12

it's not that 1

Answer 13

Which one are you referring to, then?

Answer 14

The first 1

Answer 15

\(\color{blue}{\text{Originally Posted by}}\) @Jhannybean
\[\large \sqrt{2} \cdot \sqrt[3]{2} = 2^{1/2} \cdot 2^{1/3} = 2^{(1/2) + (1/3)}\]
\(\color{blue}{\text{End of Quote}}\)

Answer 16

YES

Answer 17

And what is \(\frac{1}{2} +\frac{1}{3}\)?

Answer 18

2/5

Answer 19

it's not is it?

Answer 20

3/6 2/6

Answer 21

5/6 maybe

Answer 22

\[\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{ 2+3}{6} = \frac{5}{6}\]

Answer 23

calling jhan right now

Answer 24

oh i was right ok

Answer 25

wash the dishes, jhan
they are piling up

Answer 26

ok so whats next?

Answer 27

Therefore you can write the fraction exponent as: \(2^{5/6} \iff \sqrt[6]{2^5}\)

Answer 28

Ok thank you I get it.