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@SolomonZelman Would this one be B?
Given that one of the zeros of \(\large\color{black}{ \displaystyle P(x)=x^3+x^2-22x-40}\) is -4, that implies that P(x) is divisible by (x+4).
Divide \(\large\color{black}{ \displaystyle x^3+x^2-22x-40}\) by \(\large\color{black}{ \displaystyle x+4}\), and solve the quotient (or the result of this division) for the remaining two zeros.
@vera_ewing it also implies that P(-4) = 0 which implies that x = -4 which implies that x + 4 = 0 which impies that x + 4 is a factor of P(x).
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In other words, the fact that x + 4 is a factor of P(x) is what allows you to be able to divide P(x) by x + 4 evenly.
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