Question

cos(arcsin(-sqrt2/2)) inverse trig function help

Answer 1

@jim_thompson5910

Answer 2

show me what you have so far

Answer 3

ok

Answer 4

arcsin(-sqrt2/2)= -pi/4. Cos(-pi/4) = sqrt2/2 ??

Answer 5

your steps and final answer is correct

Answer 6

niceee

Answer 7

cot^-1(tan pi/3)

Answer 8

for this problem i got pi/6. ??

Answer 9

also correct

Answer 10

some person on here said it was wrong. are u sure its correct?

Answer 11

wolfram alpha confirms it

http://www.wolframalpha.com/input/?i=arccot%28tan%28%281%2F3%29*Pi%29%29

Answer 12

cool thanks. can u help me out on arcsin(sin 3pi)

Answer 13

sin(3pi) = ???

Answer 14

umm 0/

Answer 15

0 ?

Answer 16

yes now compute arcsin(0)

Answer 17

0?

Answer 18

i have no idea. im currently looking at my unit circle

Answer 19

yes so the final answer is 0

Answer 20

sin(0) = 0

arcsin(0) = 0

Answer 21

o ok

Answer 22

im working on some others at this moment

Answer 23

cos(sin^-1 sqrt3/2). i got 1/2??

Answer 24

correct

Answer 25

cot(sec^-1 2). i got sqrt3/3??

Answer 26

you're on a roll

Answer 27

nice

Answer 28

arccot(-sqrt3/3). i got pi/3??

Answer 29

incorrect

Answer 30

it was good while it lasted lol

Answer 31

hint: cotangent is negative in Q2 and Q4

range of arccotangent is `0 < y < pi`

so the output of arccotangent will be in Q2 if the input is negative

Answer 32

so is it - pi/3 ?

Answer 33

no, the angle will be somewhere in Q2

Answer 34

5pi/3??

Answer 35

oh nvm

Answer 36

2pi/3??

Answer 37

yep 2pi/3

Answer 38

how though?

Answer 39

because cot(2pi/3) = -sqrt(3)/3

Answer 40

so does 5pi/3

Answer 41

recall that cot(x) = 1/tan(x)

or

cot(x) = cos(x)/sin(x)

Answer 42

but 5pi/3 is in Q4

Answer 43

i dont understand the importance of the quadrants

Answer 44

how do i know which one to use?

Answer 45

the range of arccot is 0 < y < pi, so that covers Q1 and Q2

Answer 46

whatever the output of arccot it will either be in Q1 or Q2

Answer 47

will i ever use q3 or q4?

Answer 48

not with arccot

Answer 49

read this article

https://en.wikipedia.org/wiki/Inverse_trigonometric_functions

look at the table that says "The principal inverses are listed in the following table."

Answer 50

all right. sin^-1(sin 7pi/4). i got pi/4. probably wrong. dont really know this one either.

Answer 51

oh

Answer 52

what is sin(7pi/4) equal to

Answer 53

-sqrt2/2

Answer 54

now compute arcsin(-sqrt(2)/2)

Answer 55

range of arcsin: -pi/2 <= y <= pi/2

the input is negative, so the angle is in Q4

Answer 56

ummm 7pi/4??