Question

could someone help me
Solve 2x2 − 8x = −7.

Answer 1

i thought the -7 was going to be the c

Answer 2

Add the 7
2x^2-8x-7=0
a=2
b=8
c=7
\[\huge~\rm~x=\frac{ -(8) \pm \sqrt{(8)^2-4(2)(7)} }{ 2(2) }\]

Answer 3

i simplified it what would i do next to simplify it more @pooja195

Answer 4

Show me what u have

Answer 5

-8 +sqrt 8/4 or -8 - sqrt 8/4

Answer 6

@pooja195

Answer 7

none of my answers have a 1/2 in them

Answer 8

@pooja195

Answer 9

It would help if i knew what they were

Answer 10

@pooja195

Answer 11

Im not sure...
@EclipsedStar @Data_LG2

Answer 12

@ganeshie8

Answer 13

I tried it out, my answer doesn't match up either...how weird

Answer 14

\(2x^2 − 8x = −7\)

\(2x^2 - 8x + 7 = 0\)

\(a = 2\); \(b = -8\); \(c = 7\)

\(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

\(x = \dfrac{-(-8) \pm \sqrt{(-8)^2 - 4(2)(7)}}{2(2)}\)

\(x = \dfrac{8 \pm \sqrt{64 - 56}}{4}\)

\(x = \dfrac{8 \pm \sqrt{8}}{4}\)

\(x = \dfrac{8 \pm 2\sqrt{2}}{4}\)

\(x = \dfrac{2 \cdot 4 \pm 2\sqrt{2}}{2 \cdot 2}\)

\(x = \dfrac{4\pm \sqrt{2}}{ 2}\)

\(x = \dfrac{4}{2} \pm \dfrac{\sqrt{2}}{ 2}\)

\(x = 2 \pm \dfrac{\sqrt{2}}{ 2}\)

Answer 15

oh I see what you did mathstudent... I only stopped at

\(x = \dfrac{4\pm \sqrt{2}}{ 2}\)

didn't simplify lol

Answer 16

Where you stopped was a correct answer, but this way you can match one of the choices.