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Mathematics 20 Online
OpenStudy (anonymous):

i need help

OpenStudy (anonymous):

OpenStudy (anonymous):

i put the 300 and 250 in those boxes idk if im right

OpenStudy (anonymous):

So this problem would be setup much like your babysitter problem, with one part being able to be changed and one being added(or subtracted) from each other. So first off, since Marcus is earning 300 dollars per day and Lauren is earning 250 dollars per day, that gives you an indication that these values are dependent on how many days they work, so they would be multiplied by the variable x. Next, you have the one time rental fees. Marcus paid 400 dollars for one time, so this is subtracted from his initial profits, same way that Lauren's rental fee is subtracted. Therefore, you would have 300x-400 = 250x -300. Add 400 to both sides and subtract 250x from both sides, you end up with 50x = 100; x = 2. So it will take two days.

OpenStudy (anonymous):

ok thx almost done...

OpenStudy (anonymous):

@armyengineer225

OpenStudy (anonymous):

im not very good at these and im a slow learner so dont get annoyed with me haha

OpenStudy (anonymous):

I'm not getting annoyed at all, I'm pretty patient :). So from left to right on the top, let's label the equations 1, 2, 3, and the bottom 4, 5, 6. On 1, we would have 24x+12 = 24x+12, and once you subtract everything, it would be 0 = 0, so infinite. On 2, 12x+21 = 12x+18, 0 =3 so no solution. On 3, 2x+24-2x = 3x-6. 24 = 3x-6, 3x = 30, x = 10 so one solution. Try 4, 5, and 6 using my pattern.

OpenStudy (anonymous):

um, so would it be this? sorry if i got it completely wrong im still getting the hang of it

OpenStudy (anonymous):

@armyengineer225

OpenStudy (anonymous):

oh i took too long and it exited that question

OpenStudy (anonymous):

No, you got a few of them wrong. Try 4, 5, and 6 again, but remember that if you have x equal to something at the end, then there is a solution.

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