Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (freemap):

Please Help Me

OpenStudy (freemap):

The table shows the number of books donated to a library each month. The growth is exponential. Suppose the growth continues at the same rate. Use the data table to make a prediction involving exponential growth or decay. Predict the number books donated to the library in Month 8. Round to the nearest whole number.

OpenStudy (anonymous):

I predict in month 8 there will be a 315 book donation

OpenStudy (anonymous):

month #1 80 month #2 80+20=100 Month #3 100+25=125 month #4 125+30=155 month #5 155+35=185 month#6 185+40=225 month #7 225+45=315

OpenStudy (anonymous):

@freemap

OpenStudy (mathmate):

The general form of the exponential function is \(f(x)=ab^x\) From the given data, you can find a and b by substituting in the given data. For month zero, there are 80 books, so \(80=ab^0\) But since \(b^0=1\) for any non-zero b, so we found a=80. Proceed similarly for x=1 (first month) y=100, to find b. Then you will have the completed exponential function.

OpenStudy (freemap):

great explanation @Kobe95

OpenStudy (anonymous):

That's just what I predicted.

OpenStudy (anonymous):

thanks @freemap

OpenStudy (freemap):

so 225+50=275

OpenStudy (freemap):

315+50=365 i mean sorry

OpenStudy (freemap):

Is that correct?

OpenStudy (michele_laino):

Please note that, according to the reasoning of @mathmate , I got \(477\)

OpenStudy (freemap):

I didn't see where @mathmate post oh wow sorry

OpenStudy (mathmate):

@kobe95 The question states that the function is exponential. If a function has a constant second difference (5), then it is quadratic.

OpenStudy (michele_laino):

@freemap please follow the notes of @mathmate , so you should get a function like this: \[\Large y\left( x \right) = 80 \cdot {\left( {\frac{5}{4}} \right)^x}\]

OpenStudy (freemap):

having internet problems

OpenStudy (freemap):

I'm back my answer is 100

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!