Question

Vertex: (7, −1); point: (5, 11). Find the standard form of the equation

Answer 1

y= a(x-h)^2+k

Answer 2

Yes I know the equation I just don't know what to do with the points

Answer 3

vertex (h,k) Point (x,y)...plug them in

Answer 4

okay so a(7-1) +7?

Answer 5

No..look at the values for the vertex and the point and where they are in the equation

Answer 6

oh a(7-7)^2-1

Answer 7

Now solve for (a)

Answer 8

I thought 7 was h and 5 was x how come its not (5+7)^2

Answer 9

Your right but it is 5-7

Answer 10

11=a(5-7)^2 -1

Answer 11

11=a(4) -1
12=4a
3=a

Answer 12

Good now plug (a) and (h.k) back into the equation y= a(x-h)^2+k

Answer 13

y= 3(7-5)^2-1
y=12-1
y=11

Answer 14

just plug in (h,k) and (a)....so you have y= 3(x-7)^2 -1

Answer 15

so what is (x-7)^2 ?

Answer 16

oh okay and that's the standard form?

Answer 17

No that is vertex form....we need to convert to standard form which is y-ax^2+bx+c....so what is (x-7)^2 times 3?

Answer 18

y=ax^2+bx+c

Answer 19

y=3x^2+147

Answer 20

idk how to find b

Answer 21

(x-7) ^2 is (x-7) (x-7) equals x^2 -14x+49 do you see now multiply by 3