Question

help

Answer 1

we can rewrite function \(f(x)\) as follows:
\[f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}
{x - 1 + 1 = x,\quad \quad \quad x \geqslant 1} \\
{ - x + 1 + 1 = - x + 2,\quad x < 1}
\end{array}} \right.\]

Answer 2

now the requested intersection, is the solution of the subsequent algebraic system:
\[\left\{ {\begin{array}{*{20}{c}}
{y = 3x + 2} \\
{y = - x + 2}
\end{array}} \right.\]
please solve such system

Answer 3

I'm referring to the intersection point of your drawing

Answer 4

more precisely, we can write these two algebraic systems:
\[\left\{ {\begin{array}{*{20}{c}}
{y = 3x + 2} \\
{y = - x + 2}
\end{array}} \right.,\quad \left\{ {\begin{array}{*{20}{c}}
{y = 3x + 2} \\
{y = x}
\end{array}} \right.\]
and, if you solove them, their solutions are not equal to the point \((1,1)\)

Answer 5

oops..if you solve*

Answer 6

furthermore also the solution of "y=3x+2 and y=-x+2 is not equal to the point (1,1)"

Answer 7

:)