Question

solve the system using the substitution method

Answer 1

\[2y-x=5\]
\[x^2 + y^2 -25=0\]

Answer 2

in the first equation subtract 2y from both sides then multiply whold equation by -1

x=2y-5 we know x so plug that in for x in 2nd equation

(2y-5)^2 + y^2 -25=0
(4y^2 - 20y +25) + y^2 -25=0 combine like terms
5y^2-20y=0
y(5y-20) = 0 divide both sides by y and add 20 to both sides
5y=20 divide both sides by 5
y=?
plug back in y into both equations to find x

Answer 3

then let x = 0 add 25 both sides
y^2 =25 take sqaure root both sides

you can do the same let y = 0

Answer 4

beautiful, thank you very much