Calculus help please. find the maximum profit given the following revenue and cost functions R(x) =104x - x^2; C(x) = 1/3x^3 -3x^2 + 92x+37
Hmm I'm not familiar with this business stuff... Profit is Revenue minus Costs? Is that right?\[\large\rm P(x)=R(x)-C(x)\]
The formula is correct and the answer is supposed to be 35, but I don't see how they are arriving at that answer
■ \(\color{black}{\rm Step~\text{#}1}\) Find the profit function: \(\color{blue}{\rm P(x)=R(x)-C(x)}\) ■ \(\color{black}{\rm Step~\text{#}2}\) Maximize \(\color{blue}{\rm P(x)}\) \(\color{black}{\rm Steps~~maximizing~~P'(x),~~are~~as~~follows:}\) ─ Find P\('\)(x) ─ Find all critical numbers. ─ Evaluate P(x), at each critical-number, and the maximum output will be the maximum profit that you need . (The particular critical number at which you obtain the maximum output for P(x), is the price at which you obtained this maximum profit).
Additional note for finding the \(\LARGE \color{blue}{_{^{^{\bf critical~numbers}}}}\) for any function F(x). At first, you have to find f\('\)(x). Then you have 3 possible cases of critical numbers. \(\bullet\) \(\color{black}{\rm Case~\text{#}1}\) A critical number is any value of x, at which f\('\)(x) is undefined, PROVIDED that this value of x is in the domain of the f(x). \(\color{red}{\small (}\)So, if f(x) is undefined at this x-value, or if this x-value is not within the given interval of the f(x), THEN this value of x is NOT a critical number.\(\color{red}{\small )}\) \(\bullet\) \(\color{black}{\rm Case~\text{#}2}\) We set the derivative of the function to be equivalent to 0, i.e. f\('\)(x)=0 and any x-solution to the equation f\('\)(x)=0 is a critical number. \(\color{red}{\small (}\)PROVIDED that the x-solution for the equation f\('\)(x)=0 is within the domain of the f(x), and if not, then this x-value is not a critical number.\(\color{red}{\small )}\) \(\bullet\) \(\color{black}{\rm Case~\text{#}3}\) Any closed-interval boundary of f(x) is a critical number. \(\color{red}{\small (}\)So, if the interval of f(x) is [a,b] then x=a and x=b are critical numbers. If the interval of f(x) is (a,b] then only x=b is a critical number. If the interval of f(x) is [a,b) then only x=a is a critical number. If the interval of f(x) is (a,b) then none of a and b are critical number.\(\color{red}{\small )}\)
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