Question

Halp ;^;

Answer 1

Using the completing-the-square method, find the vertex of the function
f(x) = –3x2 + 6x − 2 and indicate whether it is a minimum or a maximum and at what point.

Answer 2

Maximum at (1, 1)
Minimum at (1, 1)
Maximum at (–1, 2)
Minimum at (–1, 2)

Answer 3

Do you see how the given function is in the form `f(x) = ax^2 + bx + c` ?

Answer 4

Yes. I've converted it to vertex form. Was I supposed to do that? @jim_thompson5910

Answer 5

what did you get when you converted to vertex form?

Answer 6

f(x)=-3(x+3)^2-11

Answer 7

that's incorrect

Answer 8

in this case, a = -3 and b = 6

what is the value of h = -b/(2a) ?

Answer 9

h= 1?

Answer 10

yes

Answer 11

if we plug x = 1 back into the original function, what do we get?

Answer 12

-3^2+6-2

Answer 13

9+6-2
15-2
13?

Answer 14

y = -3x^2 + 6x - 2

y = -3(1)^2 + 6(1) - 2 ... replace each x with 1

y = 1


So the vertex is (h,k) = (1,1)

Answer 15

Vertex form would be `y = -3(x-1)^2 + 1`

Answer 16

The leading coefficient `a = -3` is negative, so the vertex is a maximum point

Answer 17

Okay.. Can you help me rewrite f(x) = x^2 + 4x − 1 in vertex form?

Answer 18

now we have a = 1, b = 4, c = -1

what is the value of h = -b/(2a) ?