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Chemistry 8 Online
OpenStudy (anonymous):

please help i have a huge lab thats important!

OpenStudy (anonymous):

@Nnesha @pooja195 @TheSmartOne

TheSmartOne (thesmartone):

vague post

OpenStudy (anonymous):

i know im sorry its just a lot to type out and get no one to help haha

OpenStudy (anonymous):

its about enthalpy and such,

OpenStudy (anonymous):

calculate the energy change (q) of the surroundings (water) using the enthalpy equation i have to use this equation: q water = m × c × ΔT. it says assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. ill give the data for the metal below, its aluminum

OpenStudy (anonymous):

Measured mass of metal= 34.720g Distilled water measurement =26mL Distilled water temperature = 25.5 C Temperature of metal = 100.5 Temperature of mixture = 41.6 C

TheSmartOne (thesmartone):

I don't remember much chem, and it would take a while for me to refresh my memory... So let me tag some good chem helpers :) @aaronq @Abhisar @JoannaBlackwelder @Australopithecus @abb0t @rushrw @zale101

OpenStudy (anonymous):

okay thanks

TheSmartOne (thesmartone):

@Rushwr *

OpenStudy (anonymous):

u just multiply

TheSmartOne (thesmartone):

ok I did some research to help you out... c is the specific heat of water m is the mass so we have those values and so lets plug those in

OpenStudy (anonymous):

i have to eat dinner so ill be back in 10-15 mins, if anyone comes to help sorry for making you wait!

TheSmartOne (thesmartone):

not sure how we would calculate the change in temperature tho

OpenStudy (anonymous):

Sorry I wish I understood this but I dont

OpenStudy (anonymous):

I just figured it out

OpenStudy (anonymous):

what do u think it is

OpenStudy (anonymous):

all i know is the mass and the c part

OpenStudy (anonymous):

wht do u think u do

OpenStudy (anonymous):

plug in the numbers lol

OpenStudy (anonymous):

but i dont know the T part at the end

OpenStudy (anonymous):

I don't really know and I don't want to explain it to u wrong

OpenStudy (anonymous):

.-. ok thanks anyways

OpenStudy (photon336):

Perhaps you should take into account the temperature change of the water, because heat is being absorbed by the water and thus the temperature is raised.

OpenStudy (anonymous):

what? i dont really understand that :( i just need to find the T part, the last

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@radar @mathmate @Data_LG2 plsss

OpenStudy (mathmate):

@plohrb are you there?

OpenStudy (anonymous):

yes im here

OpenStudy (mathmate):

So the purpose/object of the experiment is to find the gain in heat of water or the specific heat of Aluminium?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i first need to do the equation above, q = m c t

OpenStudy (mathmate):

It's not a yes/no question!

OpenStudy (anonymous):

oh i misread that, sorry

OpenStudy (mathmate):

In an experiment, the first line is the objective.

OpenStudy (anonymous):

its actually both, i need to find the energy change of the water (surroundings) and the specfic heat of the metal

OpenStudy (mathmate):

Good, specific heat of Al was not mentioned in your previous posts. Have you done calculations with mc\(\Delta\)T before?

OpenStudy (anonymous):

no :c

OpenStudy (mathmate):

m=mass c=specific heat \(\Delta\)T is temperature change. So far so good?

OpenStudy (anonymous):

yepp

OpenStudy (mathmate):

Now let's make a table, and I want you to fill up the table from the given information you obtained from your lab.

OpenStudy (anonymous):

ok

OpenStudy (mathmate):

|dw:1446000456513:dw| Remember that in chemistry, trailing zeroes are significant, means you need to write them and take them into account.

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