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Solve for B. x+2^2+B^2=1^2
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@Nnesha
HI!!
hi
it is clear that \(1^1=1\)?
yep
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i suppose i meant \(1^2=1\) but whatever it is still 1
yerp
kinda hard to read did you mean \[(x+2)^2+B^2=1\]?
yeah sorry lol
and you want \(B\) in terms of \(x\) or \(x\) in terms of \(B\)?
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oh nvm it says "solve for B
\[B=\sqrt{1-(x+2)^2}\] is the simplest answer
All right thanks thats what i got.
actually that is not quite correct, should have \(\pm\) before the radical
the back of my book says. \[\sqrt{-x-4x-3}\]
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Thats what it says the answer is
@misty1212
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