Question

show how to solve the quadratic by factoring
x^2 - 4x - 32 = 0
@studygurl14
@shelbygt520

Answer 1

to solve, find two numbers that when added together = -4 and when multiplied together, equals -32

First step, factor -32

Answer 2

Find teh factors of -32. Meaning the numbers that evenly go into -32

EXAMPLE:
Factors of 6 are 1, 2, 3, and 6

Answer 3

so -2 + -2 = -4, is that a start?

Answer 4

-2*-2 don't equal -32

Answer 5

We're focusing on the factors of -32, remember? Not -4

Answer 6

oh ok my bad i was going by the original statement, "find two numbers that when added together equal -4"

Answer 7

That's the next step. :)

Answer 8

Ok so first find factors that when multiplied equal -32, thats the first step, right?

Answer 9

do the factors have to be the same two factors ?

Answer 10

yep. Sorry, I have to go eat dinner. b back tomorrow

Answer 11

and, no

Answer 12

I'll start you off. 1 and -31 are two factors. So are -1 and 32

Answer 13

so the factors would be -8 and 4 because -8*4=-32 and -8+4=-4

Answer 14

right? so whats the next step?

Answer 15

can someone help me?

Answer 16

you have the same question?

Answer 17

`so the factors would be -8 and 4 because -8*4=-32 and -8+4=-4`

correct

since the two numbers are -8 and 4, this means

`x^2 - 4x - 32` factors to `(x-8)(x+4)`

Answer 18

and thats it? theres no other steps?

Answer 19

so `x^2 - 4x - 32 = 0` becomes `(x-8)(x+4) = 0`