How would I complete the square for this problem? (will post it below)
complete teh square by first adding teh value (b/2)^2 to both sides of teh equation
where the equation is ax^2 + bx + c= 0, so in this case, b = 10
so add 25 to both sides, okay (im writing this down)
Subtract 14 from both sides to get it to the other side. x^2 + 10x = -14 Then use (b/2)^2 10/5 = 5 5^2 = 25 x^2 + 10x + 25 = -14 + 25
okay, what next @a1234
x^2 + 10x + 25 = 11 Can you factor the left side?
(x+5)(x+5)
Yep, nice job
That comes out to \(\large (x+5)^2=11\) Now, you need to get rid of the exponent by taking the square root of both sides
(x+5)(x+5) = 11 (x+5)^2 = 11 Take the square root of both sides (x+5) = sqrt11 x+5 = sqrt11 x = +/- sqrt11 - 5
So would the answer be D ?
Yep
Thank you! That helped alot! I know how to do quadratic formula, equation conversion, factoring, but for some reason completeing the square always messes me up x(
Just remember to send the constant (in this case14) to the other side to make room for completing the square. And you're welcome!
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