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Mathematics 14 Online
OpenStudy (bookworm14):

I have no idea how to work this out. (I am terrible at completing squares, sorry x( ) question posted below, thanks!

OpenStudy (bookworm14):

OpenStudy (bookworm14):

i worked through and made it to x^2 + 7x = 15 , but thats as far as I got (and im not sure ive even done it right so far)

Nnesha (nnesha):

i see what u did there to get rid of the leading coefficient would multiply by -3 or divide ?

OpenStudy (bookworm14):

are we starting with the original problem, or the step i just put there?

Nnesha (nnesha):

your step looks incorrect to me how did you get 15 ??

OpenStudy (anonymous):

ello :D

OpenStudy (bookworm14):

-3x^2 + 7x = -5 -3x^2 + 7x +5 =0 x^2 + 7x -15 = 0 x^2 +7x =15 thats how I got there >.<

Nnesha (nnesha):

i'm sorry but i'm not understanding the 3rd line -3x^2+7x+5=0 it's correct then what action did you take to get x^2+7x-15= ???? i think i'm not familiar wit this

OpenStudy (anonymous):

okay so we must complete the square, so; -3x^2+7x=-5 take half of b and square it @Bookworm14

OpenStudy (bookworm14):

@Nnesha I multiplied the 5 * -3 (commonly used in slide/divide method you multiply a*c and then divide the whole problem by -3 later) @atreyu6s3x6 but have of 7 is 3.5 ??

Nnesha (nnesha):

first we have to divide by -3 both sides then we would take half of x term \[\frac{ -3x^2 }{ -3 }+\frac{7x}{-3}=\frac{-5}{-3}\]

OpenStudy (anonymous):

oh yes! haha i forgot that step @Nnesha

OpenStudy (bookworm14):

so it becomes \[x^2 -\frac{ 7x }{ 3 } = \frac{ 5 }{ 3 }\]

OpenStudy (bookworm14):

I made the 5/3 positive because I thought the negatives signs would cancel each other out

Nnesha (nnesha):

that's correct you can change it into decimal and now we need to take of half of x term to make it perfect trinomial and then add (b/2)^2 both sides

Nnesha (nnesha):

\[\large\rm x^2+2.3x+\color{Red}{(\frac{2.33}{2})^2 }= \frac{5}{3} +\color{Red}{(\frac{2.33}{2})^2}\] i changed 7/3= into 2.33 decimal

Nnesha (nnesha):

and remember factor of that trinomal would always be \[\rm (x+\frac{b}{2})^2\] (x+ half of b term)^2

OpenStudy (bookworm14):

so would that become x+2.3x+1.32 = 2.98 ? (that is the simplified version of yours)

Nnesha (nnesha):

hmm for somehow i didn't get 2.98 at left side

OpenStudy (bookworm14):

I did it again and got 3.02 is taht what you got?

Nnesha (nnesha):

ye that' what i got

Nnesha (nnesha):

we can factor trinomal \[\large\rm\color{ReD}{ x^2+2.3x+1.32}= 3.02\] remember when we complete the square factor of this trinomial would always be \[(x+\frac{b}{2})^2 = 3.02\]

Nnesha (nnesha):

answer are in fraction form do you have calculator to convert 3.02 into fraction ?

Nnesha (nnesha):

make sense ?

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