Question

what is the value for x in this equation?
log(6x+5)-log2=log5
a) -0.833
b)-0.667
c) 0.333
d) 0.667
e) 0.833

Answer 1

\[\huge\rm \log(6x+5)-\log (2)=\log(5)\] like this ?

Answer 2

familiar with log rules ?

Answer 3

yes like that, and no not familiar

Answer 4

`quotient rule`\[\large\rm log_b x - \log_b y = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
`product rule` \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication
`power rule` \[\large\rm log_b x^y = y \log_b x\]
\[\rm \log x= \log y \rightarrow x=y\]

Answer 5

there is a negative sign so apply quotient rule
\[\large \rm \color{Red}{ \log(6x+5)-\log (2)}=\log(5)\]

Answer 6

here is an example
\[\log2 - \log 3 \rightarrow \log \frac{2}{3} \]