Help please...Using the completing-the-square method, find the vertex of the function f(x) = 2x2 − 8x + 6 and indicate whether it is a minimum or a maximum and at what point. (2 points)

Maximum at (2, −2)
Minimum at (2, −2)
Maximum at (2, 6)
Minimum at (2, 6)

Question

Help please...Using the completing-the-square method, find the vertex of the function f(x) = 2x2 − 8x + 6 and indicate whether it is a minimum or a maximum and at what point. (2 points)

 
 	
	Maximum at (2, −2)
	Minimum at (2, −2)
	Maximum at (2, 6)
	Minimum at (2, 6)

misty1212 · Answer

HI!!

lemanual · Answer

Hello : )

misty1212 · Answer

it is a parabola that opens up, so the second coordinate of the vertex is a minimum (lowest point on the curve)|dw:1446055532371:dw|

misty1212 · Answer

so it is either B or D
to choose, plug in 2 for x and see if you get -2 or 6

lemanual · Answer

Ok ty

lemanual · Answer

Can I ask 2 more?

lemanual · Answer

@misty1212  Can I ask 2 more please?

misty1212 · Answer

sure

lemanual · Answer

Rewrite f(x) = 3(x − 2)2 + 1 from vertex form to standard form. (2 points)

 
 	
	f(x) = 3x2 + 13
	f(x) = 3x2−12x + 13
	f(x) = 3x2 + 12x − 11
	f(x) = 9x2− 36x + 37

lemanual · Answer

(For this one I'm checking to see if this is right) Using the completing-the-square method, rewrite f(x) = x2 + 4x − 1 in vertex form. (2 points)

 
 	
	f(x) = (x + 2)2 + 1
	f(x) = (x + 2)2
	f(x) = (x + 2)2 + 4
	f(x) = (x + 2)2−5 <--- My answer

misty1212 · Answer

second one is right for sure

lemanual · Answer

Ok

misty1212 · Answer

$$ f(x) = 3(x − 2)^2 + 1=2(x-2)(x-2)+1=3(x^2-4x+4)-1$$ etc

misty1212 · Answer

in other words, expand and combine like terms

misty1212 · Answer

i think you get $$3x^2-12x+11$$ if i did it right

misty1212 · Answer

ooopps n

misty1212 · Answer

$$3x^2-12x+13$$ looks better

lemanual · Answer

Ty so much Sorry Took me so long to answer back