-
can someone explain this to me idk how to do this
\(\large\color{black}{ \displaystyle \lim_{ x\to\infty }\left[\frac{p(x)}{a^x}\right] }\) where p(x) is a polynomial of some (any) Nth degree and |a|>1 By L'Hospital's rule, N number of times, this limit is 0.
That is not a theorem, or not that I have ever read. Just common sense.
If you have learned L'Hospital's rule, then differentiating the equation on top and bottom, you will get the answer.
this sucker has no limit
satelite can you help me after this?
the \(10^x\) is larger than \(e^x\) but the \((-e)^x\) makes it go from negative to positive to negative etc
Oh, caret was a small enough character for me .... thanks for correcting sate.
oh right , not \(10x\) but \(10^x\) sucker goes up and down fast and furious
Saw in the denominator, but not in the numerator? Does that have any medical reasons (just kidding watching Dr. House movie)
yeah too much screen time!
@chris215 is there another part to this question? seems kind of odd
Also, in a typical for the plot of that movie
anyway, ....
no that's the whole question but thanks
yw
Join our real-time social learning platform and learn together with your friends!