Question

Can someone check my work?

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.

Answer 1

(x-6)^2 + y^2 - 4y + 4 = y^2 - 2y + 1
(x-6)^2 + y^2 - 4y = y^2 - 2y - 3
(x-6)^2 + y^2 = y^2 + 2y - 3
(x-6)^2 = + 2y - 3
1/2(x-6)^2 = - 3/2
f(x) = 1/2(x-6)^2 + 3/2

Answer 2

I think i followed the steps correctly. Its just a little hard to know if i did it right.

Answer 3

do you need it in vertex form ?

Answer 4

The answers are
A. f(x) = -1/2 (x-6)^2 + 3/2
B. f(x) = 1/2 (x-6)^2 + 3/2
C. f(x) = -1/2 (x+3/2)^2 + 6
D. f(x) = 1/2 (x+3/2)^2 + 6

Answer 5

I chose B.
I just wanted to know if i did it right.

Answer 6

yes correct good job!

Answer 7

Thanks

Answer 8

your answer is correct
but i think u skipped one step
(x-6)^2 = + 2y - 3
first add
(x-6)^2+3=2y
now divide by 2

your work
` (x-6)^2 = + 2y - 3`
`1/2(x-6)^2 = - 3/2`
looks like you divided by 2 first and then move the constant to the left side
great work keep it up!