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OpenStudy (anonymous):
What volume of 0.100 M Na3PO4 is required to precipitate all the lead(II) ions from 150.0 mL of 0.250 M Pb(NO3)2?
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OpenStudy (cuanchi):
1. write and balance the equation 2 calculate the number of moles of Pb in the 150.0ml of 0.250M Pb(NO3)2 do you have 3. by the stoiquimetry of the reaction calculate how many moles of Na3PO4 you will need to react with all the Pb 4 convert the the moles of Na3PO4 to ml of Na3PO4
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