Question

use the function y+2=-(x-3)^2 to answer the following.
A) show or explain how you would find the vertex.
B) show or explain how to find the axis of symmetry.
C) show or explain how you would find the x-intercepts.
D) show or explain how you would find the y-intercept.
E) Graph the function.

Answer 1

@shelbygt520 @studygurl14 @jim_thompson5910 @jaeuni

Answer 2

You need to set up the equations as follows y=(x-h)^2+k

Answer 3

which would be converting the function to standard form, correct?

Answer 4

Vertex form...

Answer 5

to do that, i would have to subtract 2 from both sides. giving me y=-(x-3)^2 -2
right?

Answer 6

Yes..

Answer 7

(h,k) is your vertex

Answer 8

so 3 and 2? or is it -3?

Answer 9

-3 and -2

Answer 10

It is (3,-2)

Answer 11

ok so for A, i need to write
"To find the vertex of the function, the function must first be converted to vertex form, y=(x-h)^2+k. To do this, we must subtract 2 from both sides of the function. This gives us y=-(x-3)^2-2."

Answer 12

I have to show work

Answer 13

Axis of symmetry is k

Answer 14

im still kinda hung up on the vertex part. The vertex is (3, -2) but how do i list my work for that?

Answer 15

that looks good

Answer 16

oh ok

Answer 17

ok the line axis of symmetry.. the equation is x= -b/2a right?

Answer 18

what is the formula for how to get the vertex?

Answer 19

Axis of symmetry is h sorry my error.

Answer 20

or x=h

Answer 21

I really think i need to show more work for how i got the vertex. they asked us to show work

Answer 22

y=(x-h)^2+k this is the formula in vertex form

Answer 23

Yeah and i converted the function the vertex form. But how do i know which is the vertex?

Answer 24

All you have to do is show the values that correspond to h and k.
The vertex is x= h

Answer 25

OK how do i show the values that correspond?

Answer 26

By the formula

Answer 27

ok i did this last night but i found the vertex by substituting the value of the line of symmetry into the equation but this time it doesnt ask for the line of symmetry until after finding the vertex

Answer 28

so thats why im having trouble with this

Answer 29

y intercept is (0,k)

Answer 30

for the x intercept make y = 0 and solve for x using the quadratic formula

Answer 31

Last night you were using the standard form probably..this is the vertex form

Answer 32

you're way ahead of me..

Answer 33

y=(x-h)^2+k vertex form
y = ax^2+bx+c standard form

Answer 34

i got that part

Answer 35

So when you subtracted 2 from both sides you ended up with this y=-(x-3)^2-2 correct?

Answer 36

yes

Answer 37

So we are told that (h,k) represent the vertex.
The axis of symmetry is x = h
The y intercept is (0,k)

Answer 38

so the axis of symmetry is h
which is 3 in this case?

Answer 39

and the y intercept is -2

Answer 40

(0,-2)

Answer 41

now take y=-(x-3)^2-2 and make y = 0 and solve to find your x intercepts

Answer 42

wait so make x=0?

Answer 43

im confused

Answer 44

To find x intercepts you make y = 0

Answer 45

How would i do that????