Question

URGENT:
a^2 + b^2 = c^2 ; solve for b

Answer 1

a) subtact \(a^2\) from both sides
b) take the square root

Answer 2

really you should put \(\pm\) in front of the square root, but my guess is this is a triangle problem so the negative answer would not make sense

Answer 3

yeah i get that you have to subtract a^2 but then what happens when you root it

Answer 4

you get \[b=\sqrt{c^2-a^2}\] is all

Answer 5

yeah it makes sense and i understand, but apparently it's wrong

Answer 6

did you try the + or - option he talked about earlier ?

Answer 7

would it be:
\[\sqrt{c+a} \sqrt{c-a}\]

Answer 8

I was talking about
\[b=\pm \sqrt{c^2-a^2}\]

Answer 9

let me try it. i got one more try to submit the answer and then it locks

Answer 10

well is it given b is suppose to be negative or positive?

Answer 11

or does it not say?

Answer 12

if b>0 then b=sqrt(c^2-a^2)
if b<0 then b=-sqrt(c^2-a^2)

Answer 13

nope it just says "solve the equation for the indicated variable"

Answer 14

k