Question

Could you check this for me?

Answer 1

Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC.


Which of these could be a step to prove that BC^2 = AB^2 + AC^2?

By distribution, AC^2 plus AB^2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AB^2 = BC multiplied by the quantity DC plus BD.
By distribution, AC^2 plus AD^2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AD^2 = BC multiplied by the quantity DC plus BD.

Answer 2

http://assets.openstudy.com/updates/attachments/55df39f3e4b03567e10f937f-onepieceftw-1440692740515-capturegeo.png

Answer 3

@dan815

Answer 4

@dan815

Answer 5

Im pretty sure its B

Answer 6

Just because its the only one that seems to make sense with the points given.

Answer 7

Dan?