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Mathematics 17 Online
OpenStudy (anonymous):

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OpenStudy (baru):

u have made a mistake on Q7

OpenStudy (baru):

u have chosen the option for (2x+1)^2 but the question asks for 3(2x+1)^2

OpenStudy (anonymous):

i fixed it, i believe the right answer is 12x^2+12x+3

OpenStudy (baru):

yep :)

OpenStudy (baru):

Q5 also needs fixing

OpenStudy (anonymous):

i wasn't sure about questions 1-5-6 did i solve them correctly?

OpenStudy (anonymous):

im guessing that question five is between B or C but im not sure which one

OpenStudy (baru):

whats the cube root of 4 whats the cube root of 8

OpenStudy (baru):

?

OpenStudy (anonymous):

the cube root of 4 is 1.58740105197 and of 8 is 2

OpenStudy (baru):

ok. so which of them is a perfect cube? a perfect cube is a number whose cube root does not have decimal points

OpenStudy (anonymous):

so its 8

OpenStudy (anonymous):

which means the final answer would be 8x^3+1

OpenStudy (baru):

yep

OpenStudy (baru):

have a closer look at Q1 option B, can u spot your mistake?

OpenStudy (anonymous):

is it just option B that is incorrect because i wasn't so sure about optin D either

OpenStudy (baru):

how do you decide if the options are square polynomials?

OpenStudy (baru):

whats the logic you used to choose option1?

OpenStudy (anonymous):

square polynomials are x^2−2x+1

OpenStudy (baru):

can you expand this \[(a+b)^2=?\]

OpenStudy (baru):

can you expand this \[(a+b)^2=?\]

OpenStudy (anonymous):

a^2+2ab+b^2

OpenStudy (baru):

yep so the question is asking whether or not you can write the given expression as (a+b)^2 OR (a-b)^2

OpenStudy (baru):

can you write x^2-2x+1 in the form (a-b)^2 ?

OpenStudy (anonymous):

yes

OpenStudy (baru):

how about option B?

OpenStudy (anonymous):

i dont believe so

OpenStudy (baru):

why not?

OpenStudy (anonymous):

because what i didn't notice while choosing option b and d was they had a positive sign in the place where it should be negative

OpenStudy (baru):

no! \[(a+b)^2=a^2+2ab+b^2\\(a-b)^2=a^2-2ab+b^2\] both represent perfect square polynomials

OpenStudy (baru):

if you can write it as (something)^2 it counts as a square polynomial. the -ve sign does not matter.

OpenStudy (baru):

followed?

OpenStudy (anonymous):

yes i understand now

OpenStudy (baru):

so can you write \[9x^2+24x+64\] in the form (a+b)^2 ?

OpenStudy (anonymous):

no

OpenStudy (baru):

why not?

OpenStudy (baru):

hint: the middle term(24x) should have been something else if it could have been written as (a+b)^2

OpenStudy (baru):

@kittymeow101

OpenStudy (anonymous):

because you can't put 9x^2+24x+64 in the form of (a+b)^2

OpenStudy (baru):

:) yep

OpenStudy (baru):

how about \[25x^2+80x+64\]

OpenStudy (anonymous):

yes you can

OpenStudy (baru):

ok, try writing it as (a+b)^2 what do you get?

OpenStudy (anonymous):

(5x+8)^2

OpenStudy (baru):

thats right!! :)

OpenStudy (baru):

is that all?

OpenStudy (anonymous):

yes ty for helping

OpenStudy (baru):

:)

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