Question

Ten tickets are numbered 1,2,3...10.Six tickets are
selected at random one at a time with replacement. The
probability that the largest number appearing on the selected
ticket is 7 is

Answer 1

LOL your answer is C

Answer 2

\(\large \color{black}{\begin{align}
& \normalsize \text{Ten tickets are numbered}\ 1,2,3\cdots \ 10.\ \text{Six tickets are } \hspace{.33em}\\~\\
& \normalsize \text{selected at random one at a time with replacement. The }\hspace{.33em}\\~\\
& \normalsize \text{probability that the largest number appearing on the selected }\hspace{.33em}\\~\\
& \normalsize \text{ticket is 7 is :}\hspace{.33em}\\~\\
& a). \dfrac{7^{6}-1}{10^{6}} \hspace{.33em}\\~\\
& b). \dfrac{7^{6}-6^{6}}{ 10^{6}} \hspace{.33em}\\~\\
& c). \dfrac{6^{6}}{ 10^{6}} \hspace{.33em}\\~\\
& d). \dfrac{7^{6}+6^{6}}{ 10^{6}} \hspace{.33em}\\~\\
\end{align}}\)

Answer 3

;-; whale then

Answer 4

gimmiw a minute

Answer 5

@mathmath333 be careful! @AlexandervonHumboldt2 once made a header of his tutorial 2+2? and his post was deleted. your can be as well.

Answer 6

i have freedom of speech

Answer 7

i am so sorry i am a moron tho

Answer 8

B IT IS B

Answer 9

how

Answer 10

*falls over dead* idek i made undeadknight do it

Answer 11

*sobs*

Answer 12

i tried but now i must hang my self

Answer 13

We have \(7^6\) ways to choose 6 tickets using the digits : {1, 2, 3, 4, 5, 6, 7}

Out of them, there will be \(6^6\) ways to choose 6 tickes using just the digits : {1, 2, 3, 4, 5, 6}

Therefore, there are \(7^6-6^6\) ways to choose 6 digits such that \(7\) is guaranteed to exist in the selection and being the greatest.