help
what do u need help with i will help u if u help me what grade are u in?
9th
me to 8. (03.05 MC) The table below represents the velocity of a car as a function of time: Time (seconds) x Velocity (m/s) f (x) 15 45 22 66 29 87 36 108 The average rate of change for the functions from x = 15 to x = 29 is 0.33 m/s2 and represents the car's acceleration. (5 points) Score: 0 of 5
idk that sorry
So what it's saying is which slope is greater than the slope of that graph
@AlexandervonHumboldt2
So first you need to find the slope of Relationship A
Do you know how to find slope? ^^
i do not know @narissa are we all in 9th grade we can help eachother
lol if i did i wouldnt be on here
9. (03.05 LC) The functions f(x) and g(x) are described below: f(x) = 32x + 8 g(x) = 32x −9 The graph of g(x) is obtained by shifting down the graph of f(x) by -17 units. (5 points) Score: 0 of 5
you do \[\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
what about this one
You two points are (4,2) and (8,4)
it is not -17 thought what is it 9. (03.05 LC) The functions f(x) and g(x) are described below: f(x) = 32x + 8 g(x) = 32x −9 The graph of g(x) is obtained by shifting down the graph of f(x) by units. (5 points) Score: 0 of 5
(4,2) x1 y1 (8,4) x2 y2
why 4,2 and 8,4 though
I'm answering @narissa question ^^
ohh could u answer mine after hers
\[\frac{ 4-2 }{ 8-4 }=\frac{ 2 }{ 4 }=\frac{ 1 }{ 2 }\]
is that @narissa problem
Yep
now could u answer mine
@Jesuslover14 please post your questions using Ask Question box. Posting you questions on someone questions is spam.
9. (03.05 LC) The functions f(x) and g(x) are described below: f(x) = 32x + 8 g(x) = 32x −9 The graph of g(x) is obtained by shifting down the graph of f(x) by units. (5 points) Score: 0 of 5
i did
@therefore so the answer is
is the answer a and c
yeah
9. (03.05 LC) The functions f(x) and g(x) are described below: f(x) = 32x + 8 g(x) = 32x −9 The graph of g(x) is obtained by shifting down the graph of f(x) by units. (5 points) Score: 0 of 5
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