suppose f(x)=2x-5 and g(x)= l3x-1l find the value of f(1)+g(2) how do i set this equation up?
Hey :)\[\large\rm f(\color{orangered}{x})=2(\color{orangered}{x})-5,\qquad\qquad g(\color{orangered}{x})=|3(\color{orangered}{x})-1|\]
So f(1) means, replace all x's with 1.\[\large\rm f(\color{orangered}{1})=2(\color{orangered}{1})-5\]
Do i also do that with g and then add them together?
Yes! :)
Except you're replacing the x's in g(x) with 2's, ya?
Thank you so much can i also ask you a really quick question?
sure
okay got it :)
i have to graph the inequality 4x-3y<2 but if i solve for y i got a two fractions and i dont know if i should graoh it that way or if theirs another way
graph* theres*
You could instead graph the intercepts, well it turns out that one of the intercepts is an ugly fraction anyway -_- ya just stick with solving for y in this case. You get something like this, ya?\[\large\rm y>\frac{4}{3}x-\frac{2}{3}\]You remembered to flip the inequality sign when you divided the -3 across it?
yea i got exactly that
You can graph your y-intercept, -2/3. And then just pick another point. I would recommend plugging in x=-1, that should give you a nice non-fraction coordinate.
|dw:1446164091554:dw|
alright i guess i will stick with the fractions. i was just trying to make sure i was doing it right and the most efficient way as possible
Thank you soo much!!! You were of a lot help to me. i appreciate it :D
np! ୧ʕ•̀ᴥ•́ʔ୨
^-^
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