Question

Suppose the dial on the spinner is spun 2 times in a row. Create a probability histogram for the variable X.

Answer 1

@Directrix

Answer 2

page 151

Answer 3

@dan815

Answer 4

question on page 151 about the spinner?

Answer 5

yup
but the question I posted

Answer 6

X is the number of times the dial lands on
section A.

Answer 7

probability histgram for the number of times it lands on A? is that the question?

Answer 8

yup

Answer 9

so there are 3 possible numbers for X
it could land 0 times, 1 time or 2 times

Answer 10

now we need the probability of each of these
do you know what the probability you get something other than A both times?

Answer 11

if you do not, that is fine, i will tell you
just asking

Answer 12

is it 4/9?

Answer 13

yes it is !

Answer 14

ok so far so good then lol

Answer 15

ok and for 2 is it 2/9?

Answer 16

how about the probabilty it lands on A two times (i skipped one i know)

Answer 17

sorry I meant for 1

Answer 18

ok hold on lol for 0 is 4/9 for 1 is 2/9 and for 2 is 1/9?

Answer 19

not quite
the first and last are right,that is why i skipped 1

Answer 20

you computed \[\frac{2}{9}\]by \[\frac{1}{3}\times \frac{2}{9}\] right?

Answer 21

yeah

Answer 22

but that would be the probability it lands A on the first spin, not A on the second
we have another possibility

Answer 23

namely not A, then A
of course they have the same probability, but they are two disjoint events, so you have to add them up

Answer 24

so then would it be the same as 0 based on what you are saying? it would be 4/9 again?

Answer 25

also notice that it has to land on A 0, 1 or 2 times but the probabilities need to add up to 1, and they don't the way you wrote it

Answer 26

yeah \[\frac{4}{9}\]

Answer 27

ok so the 4/9, 4/9, and 1/9?

Answer 28

yes

Answer 29

and they do add to 1 right?

Answer 30

yes

Answer 31

thank you so much for your help and can I ask one more?

Answer 32

then it looks good
i will let you draw it yourself, make sure that \(\frac{1}{9}\) is only one fourth as high as \(\frac[4}{9}\)
sure ask away

Answer 33

but let me ask a question too
where did you get this text, and what grade is it for?

Answer 34

ok and for that is ok I needed the table and from there I can make the graph :)
and for the secon one I dont get is from page 150 number 8

Answer 35

it will take a minute to find it
hold on a sec

Answer 36

ok is easier if you use ctrl+F and type 2 trials

Answer 37

i got it, but 8 means 7,8,9,10 right? four bar graphs or histogram or whatever

Answer 38

yeah but I just need 8 :)

Answer 39

we are doing even numbers and some odd numbers

Answer 40

and im only missing those 2 from that lesson :)

Answer 41

you can't really do just one, but no matter
in fact it is better if we do them all by sheer reason rather than actually making the histogram, although we can do that if you like

Answer 42

I meant as in questions numbers not from the graph

Answer 43

maybe it is not clear, but maybe it is, that the higher the probability of success, the more the histogram is skewed to the right

Answer 44

is it "match the binomial probability to the histogram" question at the bottom of the page?

Answer 45

Match the probability histogram with the description of the binomial
distribution. Assume that there are 2 trials.

Answer 46

right
so we can't really do 8, you have to match them
doing 8 doesn't really make sense since 8 is a graph

Answer 47

lets to them all without doing them
the higher the probability of success, the more likely you will have successes, the more the histogram will be skewed to the right (lower in the 0, higher in the 2)

Answer 48

I dont understand that sorry :(

Answer 49

I dont understand that sorry :(

Answer 50

if i get a success with probability \(.8\) then the probability i get two successes is \(.8\times .8=.64\) but the probability i get no successes is \(.2\times .4=.04\) a much smaller number

Answer 51

typo there, i meant \(.2\times .2=.04\)

Answer 52

so the graph will be higher on the right, lower on the left

Answer 53

I meant the graph from number 8 from the 8th question

Answer 54

is that clear more or less

Answer 55

but how did you get probability 0.8?

Answer 56

ok lets go slow
you have to match them up
it will be very very hard to look at the histogram and decide which of the four binomials it is

Answer 57

i made up the .8 as an example

Answer 58

im soo confused with this sorry

Answer 59

oh ok got it

Answer 60

i think you might be confused as to what the question is asking
you cannot really do just 8
you have to match them

Answer 61

you have A, B, C, D and 7, 8, 9, 10 and you are supposed to say
A goes with 10 for example and B goes with ...

Answer 62

ohhh ok match them to the letter questions above?

Answer 63

ok got it now

Answer 64

RIGHHHHHT

Answer 65

ok so now that we know what we have to do, lets see if we can do it

Answer 66

you don't really want to make four histograms for four different binomial probabilities just to see what you get do you? too much work

Answer 67

no lol too lazy

Answer 68

so lets to it the simple way and see if we can understand it as well

Answer 69

alright

Answer 70

the higher the probability is, the more likely you get a success (that is really just saying larger probability is larger, no real content there)
which one of A, B, C, D has the highest probability of success?

Answer 71

A

Answer 72

and which of those 4 graphs has the highest number for two successes and the lowest number for 0

Answer 73

but I think it would be 0.3 based on what you are saying because when there 2 trials graph 8 is the 3rd one fron big to small probability

Answer 74

yes i think so too

Answer 75

since you seem to be focused only on 8
i would say A goes to 10
B to 7
etc
you agree?

Answer 76

alright would you mind if I got a second opinion on this because it seems too easy 0.0

Answer 77

no not at all
i go to two doctors
we can actually check that \(.3\) gives the graph of 8 if you like

Answer 78

zero success is \(.7\times .7=.49\) and two successes is \(.3\times .3=.09\)

Answer 79

which looks pretty much like that graph right?

Answer 80

yeah

Answer 81

one success is \(2\times .3\times .7=.42\)also looksgood

Answer 82

yup

Answer 83

ok so i think we nailed that one
let me ask again, what book, what grade?

Answer 84

and thank you so much for you help :)

Answer 85

yw
because i like it, seems easy enough to understand

Answer 86

you done with these?