Question

can someone please help me with the questions I'm about to post

Answer 1

that depends on the question doesnt it?

Answer 2

\[\sqrt{8} - \sqrt{18} +\sqrt{32} \]

Answer 3

I have to simplify it but I don't know how to

Answer 4

I got the answer 4.25.

Answer 5

how

Answer 6

I just used a calculator. Sorry, I know I'm probably not much help.

Answer 7

step one is to rewrite each of this in simplest radical form

Answer 8

simplest radical form?

Answer 9

for example \[\sqrt 8=\sqrt{4\times 2}=\sqrt{4}\sqrt{2}=2\sqrt{2}\]

Answer 10

oh ok

Answer 11

find the factors inside the radical that are perfect squares, and pull them outside the radial
want to try \(\sqrt{18}\)?

Answer 12

okay

Answer 13

would it be \[\sqrt{9} \sqrt{2}\]

Answer 14

yes
then?

Answer 15

do i simplify the 9?

Answer 16

if that is what you call it
take the square root of 9

Answer 17

so 3?

Answer 18

yes, ie. \[\sqrt{18}=3\sqrt{2}\]

Answer 19

how about \(\sqrt{32}\)?

Answer 20

would it be \[\sqrt{2} \sqrt{2}\]

Answer 21

because the square root of 4 is 2

Answer 22

32 is not \(2\times 2\)

Answer 23

its 8*4 but then that's \[\sqrt{4} \sqrt{2}\] and the square root of 4 is 2

Answer 24

ok i see that but lets think smarter

Answer 25

ok

Answer 26

it is true that \(8\times 4=32\) and so you could have \[\sqrt{4\times 8}=\sqrt{4}\sqrt{8}=2\sqrt{8}\] but then you would not be done

Answer 27

still have to deal with \(\sqrt{8}\) as we did earlier

Answer 28

oh okay

Answer 29

instead of thinking of \(32\) as \(4\times 8\) how about \(32=16\times 2\)

Answer 30

okay sounds good

Answer 31

then take the square root of 16, which is 4, to get \[\sqrt{32}=4\sqrt{2}\]

Answer 32

okay

Answer 33

now we have \[\sqrt{8} - \sqrt{18} +\sqrt{32}\]\[=2\sqrt2-3\sqrt2+4\sqrt2\] combine them like you would \[2x-3x+4x\]

Answer 34

okay