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Mathematics 11 Online
OpenStudy (daniellelovee):

@satellite73

OpenStudy (daniellelovee):

@satellite73 can you help me

OpenStudy (anonymous):

hello again

OpenStudy (anonymous):

same book?

OpenStudy (daniellelovee):

hi thank you for replying fast :)

OpenStudy (daniellelovee):

yup

OpenStudy (daniellelovee):

just the next lesson

OpenStudy (anonymous):

4 and 14?

OpenStudy (daniellelovee):

yup

OpenStudy (anonymous):

ok did you do the first 3? height of distribution?

OpenStudy (daniellelovee):

yes

OpenStudy (anonymous):

did you get \(\frac{1}{3}\)?

OpenStudy (daniellelovee):

shouldnt it be 2/3?

OpenStudy (anonymous):

for the height of the distribution? (actually that is question two)

OpenStudy (anonymous):

the height should be \(\frac{1}{3}\) since the base is \(3\) units long and the area is \(1\)

OpenStudy (daniellelovee):

oh ok thank you

OpenStudy (anonymous):

but actually for the uniform distribution, although you can use the height (that is why they asked it first) you don't really need to what is the length from \(1.5\) to \(3\)? i .e. what is \(3-.15\)

OpenStudy (anonymous):

oops i meant \(3-1.5\)

OpenStudy (daniellelovee):

ok so 3/2 then?

OpenStudy (anonymous):

that is the answer to the question i asked yes, but that is not the answer to the question in the book

OpenStudy (daniellelovee):

oh ok yeah I was wondering that because it didnt seem correct since the bigger number is on top

OpenStudy (anonymous):

first of 3/2 is not a probability, it is bigger than one the total length from 1 to 4 is 3

OpenStudy (anonymous):

so your answer is \[\frac{1.5}{3}\]

OpenStudy (daniellelovee):

so 0.5 or 1/2?

OpenStudy (anonymous):

just the length of the line segment divided by the total length of the line

OpenStudy (anonymous):

yes \(\frac{1}{2}\)

OpenStudy (anonymous):

which just says the distance from \(1.5\) to \(3\) is half of the distance from \(1\) to \(4\)

OpenStudy (anonymous):

you can do it in terms of areas as well, but since the height is the same, the area will be one half the total area

OpenStudy (anonymous):

height is \(\frac{1}{3}\) base is \(\frac{3}{2}\) area is \[\frac{1}{3}\times \frac{3}{2}=\frac{1}{2}\]

OpenStudy (daniellelovee):

so 0.5/2?

OpenStudy (anonymous):

no just one half

OpenStudy (anonymous):

or \(.5\) if you prefer

OpenStudy (daniellelovee):

oh ok thank you :)

OpenStudy (anonymous):

i think i might have confused you it is a) the length of the interval divided by the total length or b) the area of the region they are the same

OpenStudy (anonymous):

for the next one, ignore the part about when the animal is weighed, it makes no difference

OpenStudy (anonymous):

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