Question

Use differentials to approximate the maximum error propagated when calculating the volume of a sphere, if radius is 5 +/- .01 meters.

Answer 1

@freckles @DanJS

Answer 2

do the differential first

Answer 3

@IrishBoy123 differential of what?

Answer 4

V=4/3πr3 ?

Answer 5

@Nnesha

Answer 6

What is the radius?

Answer 7

5 + or - .01

Answer 8

V=4/3πr^3
π or pi is equal to 3.14 22/7 and since you said the radius or 5 or -.01 you substitute that for r and cube it :)

Answer 9

no radius is 5 +/- .01
so 2 radius here 5.01 and 4.99

Answer 10

What's the full question?

Answer 11

Use differentials to approximate the maximum error propagated when calculating the volume of a sphere, if radius is 5 +/- .01 meters.
i typed the full question earlier. that is the full question

Answer 12

This is calculus isn't it?

Answer 13

yeah

Answer 14

My friend is taking calculus but he isn't on at the moment. He lives in Autralia

Answer 15

@DanJS is great but idk when he will be online.

Answer 16

@Irishboy123

Answer 17

the volume is \(\large V = \dfrac{4}{3} \pi r^3\)

the differential of that is what you need

Answer 18

@IrishBoy123

Answer 19

the differential of dV=πx2dy? @Irishboy123?

Answer 20

you mentioned a sphere at the top of the thread

\[\large V = \dfrac{4}{3} \pi r^3\]

\[dV = ???\]

Answer 21

4(pi)r^2

Answer 22

@irishboy123?

Answer 23

what is \(\dfrac{d}{dr}( r^3)\) ??

Answer 24

so 2 radius here 5.01 and 4.99