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How do infinite limits work?
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\[\lim_{x \rightarrow \infty} \frac{ 5x+7 }{ 13x^2+10x +2 }\]
Do I divide it all by the highest power term and get \[\lim_{x \rightarrow \infty} \frac{ \frac{ 5 }{ x } +\frac{ 7 }{ x^2 } }{ 13 + \frac{ 10 }{ x } + \frac{ 2 }{ x^2 } }\]
What do I do next?
now x approaches ∞ and (anything)/∞ = 0 the numerator becomes 0 and the denominator becomes 13 simplifying u get 0 :)
so. \[\frac{ 0 + 0 }{ 13 + 0 + 0 } = 0\]
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yes :)
Just to check if I got it, \[\lim_{x \rightarrow \infty} \frac{ 4x^2 + x + 6 }{ 3x^2 + 1 } = \frac{ 4 }{ 3 }\]
yea its 4/3 :)
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Perfect. Thanks guys. :)
np B)
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