f(x) = sqrx+8; g(x) = 8x - 12 Find f(g(x)).
I can help.
You remember how when it was simple, we would be given a function f(x)=x+10, where we would find f(2)=2+10?
3rd one
This is quite similar. For f(g(x)), our 'x' in our f(x), we will putin function g(x)
It looks like this... 22x−1−−−−−√
f(x) = sqrx+8; g(x) = 8x - 12 Find f(g(x) f(x)=sqrt (x+8) = g(8x-12)= sqrt (8x-12+8)
@mjmahmood You're a little off.
@mjmahmood Maddy is helping me and you're just trying to give me the answer. I want to learn how to solve it.
f(g(x)) = sqrt (8x-12+8), where now you just combine the 12 and 8 at the end.
Do you have answer choices to this?
pretty sure its f(g(x)) = sqrt (8x-4) if I combined the 12 and 8 correctly.
These are my choices
Ah. I'm thinking A.
Wait
No, maybe C. My bad.
Not sure how the square root could have that power of 8. I haven't learned of that.
We usually always have 3 or 2, but having that 2 with answer choice c specifically should be the answer.
It wants you to simplify the (8x-4) because that is not in simplest form.
This is precal but it's supposed to be stuff I learned a long time ago I just forgot it :/
Don't worry I am in pre-calc too, I am surprised at how much I have to try to remember.
I know it's not b. I mean, considering the way you gave me the function, it shouldn't be.
D doesn't make sense with the function given.
And C matches the actual simplified form of what would be 8x-4. Given radical properties and blah blah blah
Unless, my math is wrong. But I wrote it out. It's whatever you think is right. (-:
I'm trying to work it out... lol Really appreciate your help :) I don't doubt you're right just need to figure out why so i can do it no problem in the future..
Understandable. I am the same way! It's basically finding which is the simplified form of 8x-4. I am searching stuff now to help.
f(sqr(x+8)) = 8(sqr(x+8)) - 12 is what we're trying to solve, right?
f(x) = sqrx+8; g(x) = 8x - 12 Find f(g(x) f(8x-12)= sqrt (8x+8-12) = sqrt (8x-4) is what I get
I'm totally getting backwards lol sorry about that
Thats okay (-:
I can' see or understand why it the radical would have the compendium of 8 that doesn't make sense to me, not for those functions.
2^3=8 so 3^sqrt(8)=2.
And having it be 8^sqrt would produce pretty large numbers.
This is what I think
8x-4 lets set that to f(x)
Then we could maybe set that to y=8x-4. Uhm. Divding it by 4 to both sides gives y=2x-1
f(x)= sqrt 2x-1
C is your answer.Just figured it out!
Because to simplify y=8x-4, we can put 4 into 8x and -4.
Or keep it f(x). I set to y because it makes any calculations easy.
So for this, C is your answer.
Thank you :) I just to find out how it simplifies
Me too. I was trying to think of a way to simplify 8x-4 because it wasn't in simplest form. Then it dawned on me ' oh silly, set it to just f(x)=8x-4 and divide by 4 cause thats the common greatest factor between the two ' Which then yields 2x-1. So that only proves C to be correct, and probably after you apply 2^sqrt to 2x-1 you should get an equation similar or equal to 8x-4.
I found it: since 8 is not a square we need to break it into 2*4x - 4 which simplfies to 2sqr2x-1 (the imaginary number is sqr-1 * sqr4 and I guess gets lumps with the 2 on the outside of the radical)
http://algebralab.org/lessons/lesson.aspx?file=Algebra_radical_simplify.xml
Great work there @OnePieceFTW ! :)
Thank you :) Really appreciate the help!
Makes sense now, cause then times it by 2 gives 4 which then can be squared, etc.
Anytime! I think we each learned something, that's what math is about.
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