Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

which of the following is a polynomial with roots 3, 5, and -5i? a)f(x)=x^3-3x^2+25x-75 b)f(x)=x^3-3x^3+15x-25 c)f(x)=x^3-15x^2+25x-75 d)f(x)=x^3-3x^3+15x-75

OpenStudy (anonymous):

@Maddy1251

OpenStudy (maddy1251):

Do you know how to deal with imaginary numbers?

OpenStudy (anonymous):

Not really

OpenStudy (maddy1251):

An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, [note 1] which is defined by its property i2 = −1. The square of an imaginary number bi is −b2. For example, 5i is an imaginary number, and its square is −25

OpenStudy (maddy1251):

Also, have you tried plugging in other numbers?

OpenStudy (maddy1251):

Unless my calculations are wrong, which I am double checking, 3 only satisfies A. So, so far that can be the only answer.

OpenStudy (anonymous):

So you're saying A?

OpenStudy (maddy1251):

It's the only one that can yield 3. I am checking the other two numbers.

OpenStudy (anonymous):

Okay, thank you.

OpenStudy (maddy1251):

Well I read it wrong.

OpenStudy (maddy1251):

It wants the roots of the function.

OpenStudy (anonymous):

uh oh

OpenStudy (maddy1251):

No, not uh-oh. Still simple.

OpenStudy (anonymous):

to you maybe!

OpenStudy (maddy1251):

To find the roots of a function, we must factor. (No wonder why nothing would equal 0 all the way around. (-: )

OpenStudy (maddy1251):

Oh its not bad, I promise you.

OpenStudy (anonymous):

okay makes sense! I'm bad at factoring

OpenStudy (maddy1251):

Its not easy at first. Takes time. I am looking now.

OpenStudy (maddy1251):

I will have the answer in a flash (-:

OpenStudy (maddy1251):

I may have it.

OpenStudy (anonymous):

alright, awesome!

OpenStudy (maddy1251):

I am leaning towards C because so far these are the groups I am finding Group 1: (x-3) • (-25) Group 2: (x-15) • (-x2) Group one gives roots of x=3, and x=5i.

OpenStudy (maddy1251):

I am having trouble finding one that yields x=5

OpenStudy (maddy1251):

But I got 2 of 3 roots, so if I was you, thats the one I would try.

OpenStudy (anonymous):

C?

OpenStudy (maddy1251):

That's the one that yields x=3 and x=5i, and it could possibly yield root x=5. I was having trouble with all of them finding x=5.

OpenStudy (maddy1251):

Hold on.

OpenStudy (maddy1251):

@Michele_Laino want to check to see if C is correct?

OpenStudy (anonymous):

In the mean time, can you help really quickly with one I've been having trouble with? It's "which of the following represents the zeros of f(x)=x^3-2x^2-6x+12?" answer choices are: a) -2, -sqrt 6, -sqrt 6 b) 2, sqrt 6, -sqrt 6 (definitely not the answer. I chose this one last time and it was wrong) c) 2, sqrt 6, -sqrt 6 d) -2, sqrt 6, sqrt 6

OpenStudy (anonymous):

@Maddy1251 you there?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!