which of the following is a polynomial with roots 3, 5, and -5i? a)f(x)=x^3-3x^2+25x-75 b)f(x)=x^3-3x^3+15x-25 c)f(x)=x^3-15x^2+25x-75 d)f(x)=x^3-3x^3+15x-75
@Maddy1251
Do you know how to deal with imaginary numbers?
Not really
An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, [note 1] which is defined by its property i2 = −1. The square of an imaginary number bi is −b2. For example, 5i is an imaginary number, and its square is −25
Also, have you tried plugging in other numbers?
Unless my calculations are wrong, which I am double checking, 3 only satisfies A. So, so far that can be the only answer.
So you're saying A?
It's the only one that can yield 3. I am checking the other two numbers.
Okay, thank you.
Well I read it wrong.
It wants the roots of the function.
uh oh
No, not uh-oh. Still simple.
to you maybe!
To find the roots of a function, we must factor. (No wonder why nothing would equal 0 all the way around. (-: )
Oh its not bad, I promise you.
okay makes sense! I'm bad at factoring
Its not easy at first. Takes time. I am looking now.
I will have the answer in a flash (-:
I may have it.
alright, awesome!
I am leaning towards C because so far these are the groups I am finding Group 1: (x-3) • (-25) Group 2: (x-15) • (-x2) Group one gives roots of x=3, and x=5i.
I am having trouble finding one that yields x=5
But I got 2 of 3 roots, so if I was you, thats the one I would try.
C?
That's the one that yields x=3 and x=5i, and it could possibly yield root x=5. I was having trouble with all of them finding x=5.
Hold on.
@Michele_Laino want to check to see if C is correct?
In the mean time, can you help really quickly with one I've been having trouble with? It's "which of the following represents the zeros of f(x)=x^3-2x^2-6x+12?" answer choices are: a) -2, -sqrt 6, -sqrt 6 b) 2, sqrt 6, -sqrt 6 (definitely not the answer. I chose this one last time and it was wrong) c) 2, sqrt 6, -sqrt 6 d) -2, sqrt 6, sqrt 6
@Maddy1251 you there?
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