Question

help please
1-cos^2θ/sinθ
will give medal

Answer 1

Do you know what sin^2 + cos^2 = ?

Answer 2

1

Answer 3

@Nnesha

Answer 4

sin^2 + cos^2 = 1

Rewrite it with subtracting cos^2 from both sides

Answer 5

1-cos

Answer 6

1 - cos^2 = ?

Answer 7

sin^2θ

Answer 8

So your original equation was (1 - cos^2 theta)/sin theta

what is your numerator = to?

Answer 9

sin

Answer 10

Sin^2

So it is sin^2/sin^2

which = ?

I think you have the answer. I got to run.

Answer 11

it is 1

Answer 12

am i correct @Nnesha

Answer 13

is it 1

Answer 14

there is sin the at the denominator right ?

Answer 15

yes

Answer 16

\[\frac{ 1-\cos^2 \theta }{ \sin \theta }\]

Answer 17

as mentioned above replace 1-cos^2 tehta with sin^2 theta

Answer 18

1-cos

Answer 19

what do you mean ?

Answer 20

it's 1 -cos^2theta

Answer 21

\[\frac{\color{Red}{ 1-\cos^2 \theta
}}{ \sin \theta }\]
according to the identity \[\rm \sin^2 \theta +\cos^2 \theta =1 \]\[\sin^2 \theta =1-\cos^2\] right

Answer 22

yes

Answer 23

i think he made a typo at the end it should be \[\rm \frac{ \sin^2 \theta }{ \sin \theta }\]

Answer 24

now simplify that

Answer 25

sinθ

Answer 26

right

Answer 27

is that correct

Answer 28

thanks

Answer 29

np

Answer 30

@Nnesha @bluenile955 I did make a typo. Nnesha is correct.