Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (shaleiah):

Medal and fan for help

OpenStudy (anonymous):

Whatchu neeeeed love

OpenStudy (shaleiah):

Quadratic formula :(

OpenStudy (alexandervonhumboldt2):

first subtartc 6x^2 from both sides: you will get -x^2-2+10x=0

OpenStudy (alexandervonhumboldt2):

now use quadratic formula: \[\frac{ -b \pm \sqrt{b^2 -4ac}}{ 2a }\]

OpenStudy (alexandervonhumboldt2):

where ax^2+bx+c=0 substitute your values and solve

OpenStudy (shaleiah):

\[\frac{ -1\pm \sqrt{1^2-4(10)(0)} }{ 2(-1) }\]

OpenStudy (alexandervonhumboldt2):

why did you multiplied by 0?

OpenStudy (alexandervonhumboldt2):

it should be -1 instead of 0

OpenStudy (alexandervonhumboldt2):

the coefficient with x is -1

OpenStudy (alexandervonhumboldt2):

@shaleiah all of your equation is incorrorect

OpenStudy (alexandervonhumboldt2):

ax^2+bx+c=0 a=-1 b=10 c=-2

OpenStudy (alexandervonhumboldt2):

substitute these values and solve the equation:

OpenStudy (alexandervonhumboldt2):

-x^2+10x-2=0 ax^2+bx+c=0 see your mistake?

OpenStudy (shaleiah):

\[\frac{ -10\pm \sqrt{10^2-4(-1)(-2)} }{ 2(-1) }\]

OpenStudy (shaleiah):

yes

OpenStudy (alexandervonhumboldt2):

correct: now simplify this

OpenStudy (vickyisthesmartone123):

I got the exact answer for this

OpenStudy (shaleiah):

\[-10\pm \sqrt{92}\]

OpenStudy (shaleiah):

the denominator would be -2 right?

OpenStudy (alexandervonhumboldt2):

yeah

OpenStudy (alexandervonhumboldt2):

yeah correct so now (-10+-2 sqrt23)/-2

OpenStudy (shaleiah):

\[5\pm \sqrt{23}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!