Mathematics
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OpenStudy (shaleiah):
Medal and fan for help
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OpenStudy (anonymous):
Whatchu neeeeed love
OpenStudy (shaleiah):
Quadratic formula :(
OpenStudy (alexandervonhumboldt2):
first subtartc 6x^2 from both sides:
you will get -x^2-2+10x=0
OpenStudy (alexandervonhumboldt2):
now use quadratic formula:
\[\frac{ -b \pm \sqrt{b^2 -4ac}}{ 2a }\]
OpenStudy (alexandervonhumboldt2):
where ax^2+bx+c=0
substitute your values and solve
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OpenStudy (shaleiah):
\[\frac{ -1\pm \sqrt{1^2-4(10)(0)} }{ 2(-1) }\]
OpenStudy (alexandervonhumboldt2):
why did you multiplied by 0?
OpenStudy (alexandervonhumboldt2):
it should be -1 instead of 0
OpenStudy (alexandervonhumboldt2):
the coefficient with x is -1
OpenStudy (alexandervonhumboldt2):
@shaleiah all of your equation is incorrorect
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OpenStudy (alexandervonhumboldt2):
ax^2+bx+c=0
a=-1
b=10
c=-2
OpenStudy (alexandervonhumboldt2):
substitute these values and solve the equation:
OpenStudy (alexandervonhumboldt2):
-x^2+10x-2=0
ax^2+bx+c=0
see your mistake?
OpenStudy (shaleiah):
\[\frac{ -10\pm \sqrt{10^2-4(-1)(-2)} }{ 2(-1) }\]
OpenStudy (shaleiah):
yes
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OpenStudy (alexandervonhumboldt2):
correct: now simplify this
OpenStudy (vickyisthesmartone123):
I got the exact answer for this
OpenStudy (shaleiah):
\[-10\pm \sqrt{92}\]
OpenStudy (shaleiah):
the denominator would be -2 right?
OpenStudy (alexandervonhumboldt2):
yeah
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OpenStudy (alexandervonhumboldt2):
yeah correct
so now (-10+-2 sqrt23)/-2
OpenStudy (shaleiah):
\[5\pm \sqrt{23}\]