A voltaic cell operates at 298 K according to the following reaction:

3 Fe2+ (aq) → Fe (s) + 2 Fe3+ (aq)

What is the emf of this cell when [Fe3+] = 0.554 M and [Fe2+] = 7.3989E-4 M?

Question

A voltaic cell operates at 298 K according to the following reaction:

3 Fe2+ (aq) → Fe (s) + 2 Fe3+ (aq)

What is the emf of this cell when [Fe3+] = 0.554 M and [Fe2+] = 7.3989E-4 M?

wmj259 · Answer

I believe this is where you use the Nerst Equation, please double check that assumption, you are basically given the concentrations of the 2 ions. Also 298k is at 25 degrees celcius so you can use the two specific equations that use the 25 degrees celcius, I believe that equation has something like .0291 or .581 as one of the numbers divide by n(number of electrons), you gotta check which one ( i know that one of the 2 equations is a natural lo, ln,  and the other is log).