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Mathematics 17 Online
OpenStudy (anonymous):

Can anyone help me? Solve the compound inequality. 2w+5<7 and 3w-6>= 12 Check out the image below...

OpenStudy (anonymous):

OpenStudy (anonymous):

@Missiey Can you help with this one?

OpenStudy (anonymous):

give me a sec

OpenStudy (phi):

for this one 2w+5<7 add -5 to both sides. can you do that?

OpenStudy (anonymous):

2w+5 <7 -5 -5 ----------- 2w < 2 Correct?

OpenStudy (phi):

yes. now divide both sides by 2

OpenStudy (anonymous):

2w < 2 /2 < /2 -------- w < 1

OpenStudy (phi):

yes. that means w is smaller than 1 (notice the "small end" of the < is next to the w) so the answer is (so far) , 1) we need to find what w is bigger than

OpenStudy (phi):

3w-6>= 12 any ideas? what is a good thing to add to both sides?

OpenStudy (anonymous):

3w - 6 >= 12 +6 >= +6 --------------- 3w >= 18 /3 >= /3 ------------ w >= 6 Correct?

OpenStudy (phi):

yes. that means w is equal to or bigger than 6 so we have w is smaller than 1 and at the same time 6 or bigger guess what? there is no number that works.

OpenStudy (anonymous):

So the answer is the zero with the / through it??

OpenStudy (anonymous):

|dw:1446247266926:dw|

OpenStudy (phi):

yes, the "null set" which is a fancy way to say, no solution

OpenStudy (anonymous):

Thanks! Could you help me with a few more? Just to make sure i'm doing them right?

OpenStudy (anonymous):

4x - 5 <= 11 and 3x - 4 <= - 16

OpenStudy (anonymous):

4x - 5 <= 11 +5 <= + 5 --------------- 4x <= 16 /4 <= /4 ----------- x <= 4

OpenStudy (anonymous):

@Alireem94 you are in good hands I am going to jump on aleks and get some work done..here if u need

OpenStudy (anonymous):

3x - 4 <= -16 +4 <= +4 --------------- 3x <= -12 /3 <= /3 -------------- x <= -4

OpenStudy (phi):

yes. so you have x<=4 and at the same time x<= -4 both have to be true at the same time. what do you think?

OpenStudy (anonymous):

I really have no idea how to determine this part

OpenStudy (phi):

The first idea is you can simplify the conditions if you have to be less than or equal to -4, then saying oh and we want to be less than 4 is a useless thing to add. Do you agree?

OpenStudy (anonymous):

Yes

OpenStudy (phi):

so x<=-4 and x<=4 simplifies to x<= -4 what is the biggest x can be ?

OpenStudy (anonymous):

4?

OpenStudy (phi):

\[ x \le -4\] what is the biggest x can be ?

OpenStudy (anonymous):

-4

OpenStudy (phi):

is x allowed to be -4 ?

OpenStudy (phi):

yes, that is what the \( \le \) means. If it were just <, then x would not be

OpenStudy (anonymous):

Oh ok... So x is less than OR equal to -4

OpenStudy (phi):

now we can fill in the answer we want ( or [ smallest , biggest ) or ] we use ] for \( \le\) and we use ) for <

OpenStudy (phi):

we know the biggest number x can be, -4 and it can equal -4, so we use ] so we have , -4] now what is the smallest x can be ?

OpenStudy (phi):

x<= -4 has no restriction on how negative x can be. -1000, -100000, .... so we say x can be -infinity= \( - \infty\) for infinity, we always use the ( and never [ as the bracket because infinity is not a number, it is more like an "idea":

OpenStudy (anonymous):

So it's (−∞, -4]

OpenStudy (phi):

yes

OpenStudy (anonymous):

Thank you!!!

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