Question

will give medal and fan
Secx+tanx/secx +tanx-cosx

Answer 1

well use what you know

sec = 1/cos
tan = sin/cos

so the problem is

\[\frac{1}{\cos(x)} + \frac{\frac{\sin(x)}{\cos(x)}}{\frac{1}{\cos(x)}} + \frac{\sin(x)}{\cos(x)} - \cos(x)\]

a lot of common denominators here...

but start by simplifying the fraction

Answer 2

Ok

Answer 3

how would i simplfy

Answer 4

plz help

Answer 5

\[\frac{ \frac{ \sin(x) }{ \cos(x) } }{ \frac{ 1 }{ \cos(x) } }\]

Answer 6

You need to simplify that.

Answer 7

sinx

Answer 8

correct now write out you problem again and determine a common denominator

Answer 9

cosx

Answer 10

is it cos x

Answer 11

yes

Answer 12

so is that my answer

Answer 13

no..rewrite the equation with the common denominator

Answer 14

\[\cos /\sin /\cos/1\]

Answer 15

1+sin(x)cos(x)+sin(x)-cos(x^2) all over cos(x)...

Answer 16

now i just simplfy

Answer 17

yes..

Answer 18

1+sin(x)cos(x)+sin(x)-cos(x^2) this is all you have to simplify

Answer 19

sin2(x)+sin(x)cos(x)+sin(x)

Answer 20

is that right

Answer 21

Very good but you can break out the sin(x)

Answer 22

ok

Answer 23

sin(x)(sin(x)+cos(x)+1)

Answer 24

Good job