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Solve. x2-49 = 0 A) ±49 B) ±12 C) ±7 D) ±6 @Lily2913
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C.
x^2 = 49 \[x=\sqrt{49}\] \[x = \pm7\]
Add 49 to both sides. so now you have x = \[\sqrt{49}\] and the square of 49 is 7
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