Question

suppose you have
a = -0.55
b = 12
c = 15
Then which one of the quadratic functions will you use?

Answer 1

need more info to answer that one

Answer 2

^

Answer 3

Nah, you don't need more information. You just use the quadratic formula

Answer 4

then go right ahead pal

Answer 5

we can olny use quadratic functions

Answer 6

not quadratic equation

Answer 7

You need to graph?

Answer 8

are you referring to ax^2+bx+c ?

Answer 9

any function

Answer 10

send me a screenshot of the problem. you're not making any sense

Answer 11

that is the question

Answer 12

we can use any quadratic function to solve the answer

Answer 13

OK, good luck then

Answer 14

lets use ax^2 + bx + c

Answer 15

-0.55x^2 + 12x + 15
then how will you solve it?

Answer 16

Use the quadratic formula -b +- sqrt(b^2 - 4ac)/ 2a

Answer 17

I assume you're trying to find the roots of a function whose coefficients are as mentioned.

Answer 18

you can also try desmos

Answer 19

but it is quadratic functions

Answer 20

This is the quadratic function: y = -0.55x^2 + 12x + 15.
Its graph is a parabola.

If you want to find where the graph of the quadratic function intersects the x-axis, you can use the Quadratic Formula for that.

The y-value of the points on the x-axis is 0, so set y equal to 0.

0 = -0.55x^2 + 12x + 15

The two x values you get from solving that equation are the x-intercepts of the quadratic function. They are also known as roots or zeroes of the function.

Answer 21

yeah but how to convert from standard form to vertex form

Answer 22

@Directrix

Answer 23

@imqwerty

Answer 24

what do u knw about the vertex form

Answer 25

a(x-h)^2 + k

Answer 26

sorry

Answer 27

how to covert it to (x, ) (x, )

Answer 28

like when we solve the standard form then we get some thing like this (x, ) (x, ).
that what i want

Answer 29

qwerty

Answer 30

LOL ok XD

Answer 31

do u want to find the vertex cordinates?

Answer 32

the x intercepts

Answer 33

the x intercepts are the roots of this equation
and u want to find the roots by converting it to vertex form?

Answer 34

morel ike intercept form

Answer 35

what do u knw about intercept form

Answer 36

a(x-p)(x-q)

Answer 37

ok
so lets convert it into this form

we have
ax^2 +bx+c=0

we need to convert it into a(x-p)(x-q)
ax^2 +x[-p-q]+pq=0

compare it with ax^2 +bx+c=0

we see that
b=-p-q
c=pq

u have b and c u can find p and q
then just substitute pa nd q in ur equation :D

Answer 38

i am in 10th man

Answer 39

so

Answer 40

how about just solve for standard form, we did not learn that yet

Answer 41

yaar

Answer 42

(:

Answer 43

do you know how to solve the standard form

Answer 44

QWERTY

Answer 45

well what u call as standard form is basically this-
ax^2 +bx+c=0

u can solve it in diff ways

the best way is to use the formula like directrix did

Answer 46

remember ac = -0.75, b = 12

Answer 47

QWERTY

Answer 48

dudeeeee

Answer 49

you know what screw this question

Answer 50

where are u stuck?

Answer 51

Adi3 , If only you told us clearly what you wanted in the first place I could have helped you and you wouldn't have gone through all this grief.
Now you're just frustrated and you don't even have an answer

Answer 52

yeah

Answer 53

so, are you after the vertex form of the quadratic equation?

Answer 54

or do you want the x intercepts?

Answer 55

x intercepts