Consider the function f(x)=cosh(3x). For the following questions, express your answers in terms of exponential functions. a) Find the local linearization of f(x) near x=1 b) Does the approximation overestimate or underestimate f(2)? I really have no idea where to start with this.
How I would start this and Im not 100% sure but i would plug 1 into x
It should look like cos(3*1) then plug that into your calculator for part A For part B take and do the same thing except with the number 2
this is how u start: linear approximation \[\Delta y= f'(x_0) \Delta x\]
So, would I need to differentiate cosh(x) first?
yep
So that would come to \[\frac{ e^x-e^-x }{ 2 }\] ?
i'm sorry xD i dont remember derivates of cosh or anything about hyperbolic functions, but i know what the question is asking for, i can help you with the steps
okay i know I got my derivative wrong, it is supposed to be a + instead of -, but what would I do from here?
you evaluate f '(x) at x_0, here it says linearize near x=1, so x_0=1 substitute, get a number for f '(x_0)
@Revircs following?
yeah, im just writing everything down for notes, sorry
no prob :)
so after evaluating at x=1, I would get to \[\frac{ e^1+e^-1 }{ 2 }\]
or \[\frac{ e+1/e }{ 2 }\]
ok, you can leave it that way for now, but later use a calculator, and actually find a number ok so now were done with f ' ( ) the question asks you to find f (2) using the linear approx, \(\Delta x\) represents change in x, so how much has x changed when we move from f(1) to f(2) ?
oh, okay. my professors usually have us leave it in exact form. So from there I would evaluate at f(x)=2 and find the difference?
noo... you should realize that \(\Delta x=1\) substitute, f '(1) and \(\Delta x =1\) to find \(\Delta y \)
oh, so since the change in x is just 1, the change in y would be the same as the derivative in this case?
yes
i hope you are catching on to what linear approximation means, essentially, we are assuming that the graph of f(x) between the points x=1 and x=2 is a straight line with the slope f ' (1) |dw:1446362283967:dw|
* sorry the two points marked on the x axis are 1 and 2
|dw:1446362420404:dw|
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